Given a non-negative integer num, return the number of steps to reduce it to zero. If the current number is even, you have to divide it by 2, otherwise, you have to subtract 1 from it.

 

Example 1:

Input: num = 14
Output: 6
Explanation: 
Step 1) 14 is even; divide by 2 and obtain 7. 
Step 2) 7 is odd; subtract 1 and obtain 6.
Step 3) 6 is even; divide by 2 and obtain 3. 
Step 4) 3 is odd; subtract 1 and obtain 2. 
Step 5) 2 is even; divide by 2 and obtain 1. 
Step 6) 1 is odd; subtract 1 and obtain 0.
Example 2:

Input: num = 8
Output: 4
Explanation: 
Step 1) 8 is even; divide by 2 and obtain 4. 
Step 2) 4 is even; divide by 2 and obtain 2. 
Step 3) 2 is even; divide by 2 and obtain 1. 
Step 4) 1 is odd; subtract 1 and obtain 0.
Example 3:

Input: num = 123
Output: 12
 

Constraints:

0 <= num <= 10^6

这题算法太直接了,按着描述写即可,没有难度。

class NumberOfStepsToReduceANumberToZero : public Solution {
public:
    void Exec() {

    }
    int numberOfSteps (int num) {
        int step = 0;
        while (num != 0) {
            if (num % 2 == 0) {
                num /= 2;
            } else {
                num--;
            }
            step++;
        }
        return step;
    }
};
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作者

sryan
today is a good day