Given a m * n matrix of distinct numbers, return all lucky numbers in the matrix in any order.
A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
Example 1:
Input: matrix = [[3,7,8],[9,11,13],[15,16,17]]
Output: [15]
Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column
Example 2:
Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]
Output: [12]
Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 3:
Input: matrix = [[7,8],[1,2]]
Output: [7]
Constraints:
m == mat.length
n == mat[i].length
1 <= n, m <= 50
1 <= matrix[i][j] <= 10^5.
All elements in the matrix are distinct.
这题也直接按照题意来遍历矩阵就行了。
class LuckyNumbersInAMatrix : public Solution {
public:
void Exec() {
}
vector<int> luckyNumbers (vector<vector<int>>& matrix) {
vector<int> res;
for (int row = 0; row < matrix.size(); row++) {
int luckyNumber = 1e6;
int index = 0;
for (int col = 0; col < matrix[row].size(); col++) {
if (matrix[row][col] < luckyNumber) {
luckyNumber = matrix[row][col];
index = col;
}
}
bool match = true;
for (int row = 0; row < matrix.size(); row++) {
if (luckyNumber < matrix[row][index]) {
match = false;
break;
}
}
if (match) {
res.push_back(luckyNumber);
}
}
return res;
}
};