1614. Maximum Nesting Depth of the Parentheses

A string is a valid parentheses string (denoted VPS) if it meets one of the following:

It is an empty string "", or a single character not equal to "(" or ")",
It can be written as AB (A concatenated with B), where A and B are VPS's, or
It can be written as (A), where A is a VPS.
We can similarly define the nesting depth depth(S) of any VPS S as follows:

depth("") = 0
depth(C) = 0, where C is a string with a single character not equal to "(" or ")".
depth(A + B) = max(depth(A), depth(B)), where A and B are VPS's.
depth("(" + A + ")") = 1 + depth(A), where A is a VPS.
For example, "", "()()", and "()(()())" are VPS's (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS's.

Given a VPS represented as string s, return the nesting depth of s.

 

Example 1:

Input: s = "(1+(2*3)+((8)/4))+1"
Output: 3
Explanation: Digit 8 is inside of 3 nested parentheses in the string.
Example 2:

Input: s = "(1)+((2))+(((3)))"
Output: 3
Example 3:

Input: s = "1+(2*3)/(2-1)"
Output: 1
Example 4:

Input: s = "1"
Output: 0
 

Constraints:

1 <= s.length <= 100
s consists of digits 0-9 and characters '+', '-', '*', '/', '(', and ')'.
It is guaranteed that parentheses expression s is a VPS.

这题很简单，维护最大的深度和当前深度就行了。

class MaximumNestingDepthOfTheparentheses : public Solution {
public:
    void Exec() {

    }
    int maxDepth(string s) {
        int curDepth = 0;
        int depth = 0;
        for (auto c : s) {
            if (c == '(') {
                curDepth++;
                if (curDepth > depth) depth = curDepth;
            } else if (c == ')') {
                curDepth--;
            }
        }
        return depth;
    }
};