You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.

Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.

Return true if a and b are alike. Otherwise, return false.

 

Example 1:

Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:

Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.
Example 3:

Input: s = "MerryChristmas"
Output: false
Example 4:

Input: s = "AbCdEfGh"
Output: true
 

Constraints:

2 <= s.length <= 1000
s.length is even.
s consists of uppercase and lowercase letters.

这题直接遍历即可。


class DetermineIfStringHalvesAreAlike : public Solution {
public:
    void Exec() {

    }
    bool halvesAreAlike(string s) {
        int c1 = 0, c2 = 0;
        for (int i = 0; i < s.size(); i++) {
            char uc = toupper(s[i]);
            if (uc != 'A' && uc != 'E' && uc != 'I' && uc != 'O' && uc != 'U') {
                continue;
            }
            if (i >= s.size() / 2) {
                c2++;
            } else {
                c1++;
            }
        }
        return c1 == c2;
    }
};
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sryan
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