You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.
Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.
Return true if a and b are alike. Otherwise, return false.
Example 1:
Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:
Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.
Example 3:
Input: s = "MerryChristmas"
Output: false
Example 4:
Input: s = "AbCdEfGh"
Output: true
Constraints:
2 <= s.length <= 1000
s.length is even.
s consists of uppercase and lowercase letters.
这题直接遍历即可。
class DetermineIfStringHalvesAreAlike : public Solution {
public:
void Exec() {
}
bool halvesAreAlike(string s) {
int c1 = 0, c2 = 0;
for (int i = 0; i < s.size(); i++) {
char uc = toupper(s[i]);
if (uc != 'A' && uc != 'E' && uc != 'I' && uc != 'O' && uc != 'U') {
continue;
}
if (i >= s.size() / 2) {
c2++;
} else {
c1++;
}
}
return c1 == c2;
}
};