Given a reference of a node in a connected undirected graph.
Return a deep copy (clone) of the graph.
Each node in the graph contains a val (int) and a list (List[Node]) of its neighbors.
class Node {
public int val;
public List<Node> neighbors;
}
Test case format:
For simplicity sake, each node's value is the same as the node's index (1-indexed). For example, the first node with val = 1, the second node with val = 2, and so on. The graph is represented in the test case using an adjacency list.
Adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.
The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.
Example 1:
Input: adjList = [[2,4],[1,3],[2,4],[1,3]]
Output: [[2,4],[1,3],[2,4],[1,3]]
Explanation: There are 4 nodes in the graph.
1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
Example 2:
Input: adjList = [[]]
Output: [[]]
Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.
Example 3:
Input: adjList = []
Output: []
Explanation: This an empty graph, it does not have any nodes.
Example 4:
Input: adjList = [[2],[1]]
Output: [[2],[1]]
Constraints:
1 <= Node.val <= 100
Node.val is unique for each node.
Number of Nodes will not exceed 100.
There is no repeated edges and no self-loops in the graph.
The Graph is connected and all nodes can be visited starting from the given node.
这题让我们深拷贝一个无向图。数据结构中每个节点的值给出了,并且也给出了邻接节点。
我们从根节点开始遍历,假设该节点没有被拷贝过,则拷贝,然后遍历邻居,也按该规则,然后将该拷贝的邻居节点接到拷贝过的根节点上即可。
// Definition for a Node.
class Node {
public:
int val;
vector<Node*> neighbors;
Node() {
val = 0;
neighbors = vector<Node*>();
}
Node(int _val) {
val = _val;
neighbors = vector<Node*>();
}
Node(int _val, vector<Node*> _neighbors) {
val = _val;
neighbors = _neighbors;
}
};
class CloneGraph : public Solution {
public:
void Exec() {
}
Node* cloneGraph(Node* node) {
if (nullptr == node) return nullptr;
unordered_map<Node*, Node*> copyMap {{node, new Node(node->val)}};
deque<Node *> nodes;
nodes.push_back(node);
while (!nodes.empty()) {
Node *cur = nodes.back();
nodes.pop_back();
for (int i = 0; i < cur->neighbors.size(); i++) {
Node *neigh = cur->neighbors[i];
auto it = copyMap.find(neigh);
Node *cnode = nullptr;
if (copyMap.end() == it) {
cnode = new Node(neigh->val);
nodes.push_back(neigh);
copyMap[neigh] = cnode;
} else {
cnode = it->second;
}
copyMap[cur]->neighbors.push_back(cnode);
}
}
return copyMap[node];
}
};