The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,

F(0) = 0, F(1) = 1
F(n) = F(n - 1) + F(n - 2), for n > 1.
Given n, calculate F(n).

 

Example 1:

Input: n = 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.
Example 2:

Input: n = 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.
Example 3:

Input: n = 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.
 

Constraints:

0 <= n <= 30

这题没啥好说的,记得上学的时候还做过,递归基础题。


class FibonacciNumber : public Solution {
public:
    int fib(int n) {
        if (n <= 1) return n;
        return fib(n - 2) + fib(n - 1);
    }
};
共 1 条回复
  
[email protected]   (游客) 2021-10-10 08:34
我记得有不递归的写法 用动态规划
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sryan
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